(6x+1)(2x^2-9x-5)=0

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Solution for (6x+1)(2x^2-9x-5)=0 equation: 


Simplifying
(6x + 1)(2x2 + -9x + -5) = 0

Reorder the terms:
(1 + 6x)(2x2 + -9x + -5) = 0

Reorder the terms:
(1 + 6x)(-5 + -9x + 2x2) = 0

Multiply (1 + 6x) * (-5 + -9x + 2x2)
(1(-5 + -9x + 2x2) + 6x * (-5 + -9x + 2x2)) = 0
((-5 * 1 + -9x * 1 + 2x2 * 1) + 6x * (-5 + -9x + 2x2)) = 0
((-5 + -9x + 2x2) + 6x * (-5 + -9x + 2x2)) = 0
(-5 + -9x + 2x2 + (-5 * 6x + -9x * 6x + 2x2 * 6x)) = 0
(-5 + -9x + 2x2 + (-30x + -54x2 + 12x3)) = 0

Reorder the terms:
(-5 + -9x + -30x + 2x2 + -54x2 + 12x3) = 0

Combine like terms: -9x + -30x = -39x
(-5 + -39x + 2x2 + -54x2 + 12x3) = 0

Combine like terms: 2x2 + -54x2 = -52x2
(-5 + -39x + -52x2 + 12x3) = 0

Solving
-5 + -39x + -52x2 + 12x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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